Question

differentiate the following function with respect to x

f(x) = 4√x/1-3x​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

y`= (vu` - uv`) / v^2

let f(x) = y = 4√x / (1-3x)

dy/dx = { (1-3x)* (4/√x) - (4√x * (-3) ) } /(1-3x)^2

= { (4-12x)/√x - 12√x } / (1-3x)^2

= (4-12x -12x) / (1-3x)^2

= 4(1-6x) / (1-3x)^2