Differentiate the following :
log root x-1 / root x+1
Answers
Answered by
2
Answer:
Step-by-step explanation:
dy/dx = d/dx log root under x-1 / root under x+1
dy/dx = root under x+1 / root under x-1 * 1/(x+1)^2/3 * 1/root under x-1
dy/dx = (x+1)^2/ x-1
Similar questions