Math, asked by zakariya89, 10 months ago

differentiate the following. (logx)^x-(x)^logx​

Answers

Answered by Amartya7
2

Answer:

- (log x) x ^ (log x -1)

Step-by-step explanation:

dy/dx = 0 - (log x) x ^ (log x -1)

= - (log x) x ^ (log x -1)

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