Differentiate the following w.r.t. x
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Answer:
2xe^x².tan(e^x²)
Step-by-step explanation:
d/dx log[sec(e^x²)]
applying substitution method for differentiation.
let sec(e^x²) = u
e^x² = v
x² = w
=> d/du logu. d/dv secv.d/dw e^w.d/dx x²
=> 1/u . sec v tan v . e^w . 2x
=> 1 / [sec(e^x²)] . sec(e^x²)tan(e^x²).e^x².2x
=> tan(e^x²) . e^x² . 2x
=> 2xe^x².tan(e^x²)
Hope this helps you
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