differentiate the following w.r.t x (5x²+6)(2x³+4)
Answers
Answered by
2
d(u∗v)
=u
dx
dv
+v
dx
du
and. . .
dx
dx
n
=nx
n−1
y
′
=(5x
2
+6)∗(2∗3x
3−1
)+(2x
3
+4)(5∗2x
2−1
)
y
′
=30x
4
+36x
2
+20x
4
+40x
y
′
=50x
4
+36x
2
+40x
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