Differentiate the following w.r.t x
(i) 3x + 5
( ii) x-2
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(i) d(3x + 5)/dx = 3dx/dx + d5/dx = 3x1 + 0 = 3
(ii) d(x - 2)/dx = dx/dx - d2/dx = 1 - 0 = 1
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Answer:
i)3
ii)1
Explanation:
i)d/dx(3x+5)=d/dx(3x)+d/dx(5)
=3(d/dx(x))+0
=3
ii)d/dx(x-2)=d/dx(x)-d/dx(2)
=1-0
=1
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