Question

Differentiate the following w.r.t. x y= (x^ + 2)× sinx​

Answer 1

Answer:

dy/dx = (x^2 + 2)[x^2cosx + 2cosx + 4xsinx]

Step-by-step explanation:

y= (x^2 + 2)^2sinx​

Applying uv method,

dy/dx = (x^2 + 2)^2 cosx + 2(x^2 + 2) 2xsinx

dy/dx = (x^2 + 2)[x^2cosx + 2cosx + 4xsinx]