differentiate the following with respect to X
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On differentiating using chain rule
y = (x³+sinx)⁵
using formula dxⁿ/dx = n*x^(n-1). (so we assume x³+sinx to be a single variable say k and differentiate k^n first and then k using chain rule)
we get dy/dx = 5(x³+sinx)⁴ * d(x³+sinx)/dx
using formula d(x³+sinx)/dx = dx³/dx + d(sinx)/dx and dsinx/dx = cosx
dy/dx = 5(x³+sinx)⁴ * (3x²+cosx)
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Differentiation
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