differentiate the function
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its simple cause above expression is actually expansion of eˣ
eˣ = 1 + x/1! + x²/2! + x³/3! + ........................ = y
therefore dy/dx = d(eˣ)/dx = eˣ
any doubt, ask?
eˣ = 1 + x/1! + x²/2! + x³/3! + ........................ = y
therefore dy/dx = d(eˣ)/dx = eˣ
any doubt, ask?
parisakura98pari:
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Since y is the expansion of e^x
dy/dx=y itself as the derivative of e^x is e^x itself.
Hope it's right.
dy/dx=y itself as the derivative of e^x is e^x itself.
Hope it's right.
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