Question

differentiate the function of x 4 sin x + 3 cos x​

Answer 1

Given:

Function in terms of 'x' is given as:

4.sinx+3.cosx=y(let)

To find:

The derivative of y w.r.t. x

★Solution★

$\frac{dy}{dx} = \frac{d}{dx} [4.sinx + 3.cosx]$

.

Using the sum rule:

$y' = \frac{d}{dx} [4.sinx] + \frac{d}{dx} [3.cosx]$

$y' = (4.cosx )+ (3)( - sinx)$

★Answer★

$y' = - 3.sinx + 4.cosx$

Answer 2

Step-by-step explanation:

y=4xsinx+3cosx

y'= 4.(x.sinx)-3sinx

y'= 4(xcosx+sinx)-3sinx

y'= 4xcosx+4 sinx-3sinx

y'=4xcosx+sinx