Question

differentiate the function tanx​

Answer 1

Answer:

dtan x/dx

d(sinx/cosx)/dx

=sec^2x

Answer 2

$\: let \: y \: = \tan \: x \: \\ \\ \frac{dy \: }{dx \: } = \frac{d \: \: \tan \: x}{dx \: } \\ \\ \frac{dy \: }{dx \: } = { \sec \: }^{2} x$

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