Question

Differentiate the function w.r.t. x if y= e^5logx + 2x​

Answer 1

Answer :-

• $\sf{\dfrac{dy}{dx} = }$$\boxed{\textsf{\textbf{\red{5x⁴ + 2}}}}$

Given :-

• $\sf{y = e^{5lnx} + 2x}$

To find :-

• The value of $\sf{\dfrac{dy}{dx}}$

Solution :-

$\sf{➪\:\dfrac{dy}{dx}}$$\sf{=\dfrac{d}{dx}(e^{5lnx} + 2x)}$

$\sf{=\dfrac{d}{dx}(e^{lnx^5} + 2x)}$

$\sf{=\dfrac{d}{dx}(x^5 + 2x)}$

$\sf{=\dfrac{d}{dx}(x^5) + \dfrac{d}{dx}(2x)}$

$=$ $\sf{\red{5x⁴ + 2}}$