Question

differentiate the function with respect to x

Answer 1

let Y =2 √cot(x²)
then dy/dx = 2 (1/2 *1/(√cot(x²)) * -cosec(x²) * 2x )
  further solving                = -2x ( cosec(x²) / √cot(x²) )
 writing cosecx² into sinx², we get
dy/dx = -2x (1 / ( √sin²(x²) * cot(x²) )
then write cot(x²) into cos(x²) / sin(x²) , we get
dy/dx = -2x ( 1 / √(cos(x²) * sin(x²) )
in the root it is teh formula of sin2x = 2 sinx * cosx ,by using that we get
dy/dx = -8x / ( √sin2x )
so it is the answer

Answer 2

hope its clear............