Question

differentiate the question​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

let us assume the question as y

y=(sin x)^log x

take log on both sides

log y=log x*log sin x

differentiating with respect to x

1/y dy/dx=(log sin x)/x+log x*(1/sin x)*cos x

dy/dx=y(log sin x)/x+log x*(1/sin x)*cos x

put y=(sin x)^log x

we get

dy/dx=(sin x)^log x{(log sin x)/x+log x*(1/sin x)*cos x}