Differentiate the y=Logx-cos x+sinx
Answers
Answered by
0
Step-by-step explanation:
y=logx - cos X + sin X
dy/dx = 1/X +sin X + cos X
complete you answer
Answered by
0
Answer:
1/x +sinx+cosx
Step-by-step explanation:
d/dx(cosx)=-sinx
d/dx(sinx)=cosx
d/dx(logx)=1/x
Similar questions