Question

differentiate the y= sinx-tanx​

Answer 1

Answer:

First, let y=sin(x)tan(x) . Next, take the natural logarithm of both sides and use a property of logarithms to get ln(y)=tan(x)ln(sin(x)) . =1+ln(sin(x))sec2(x) . Multiplying both sides by y=sin(x)tan(x) now gives the final answer to be ddx(sin(x)tan(x))=(1+ln(sin(x))sec2(x))⋅sin(x)tan

Answer 2

Explanation:

y = sinx – tanx

dy/dx = cosx – sex^2 x