Differentiate w.r.t x: (3 3 − 8 − 1) 5
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Answer:
your answer will come 5(3x²-2)(x³-2x-1)^4
Step-by-step explanation:
Let y=(x 3 −2x−1) ^5
Put u=x 3 −2x−1. Then y=u ^5
∴ dy/du=d/du (u^5)=5u^4
=5(x3−2x−1)4 and du/dx = d/dx (x 3 −2x−1)
=3×2−2×1−0
=3×2−2
∴dy/dx=dy/du*du/dx
=5(x^ 3 −2x−1) ^ 4 (3x^ 2 −2)
=5(3x ^2 −2)(x^ 3 −2x−1)^4
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