Question

differentiate w.r.t 'x'
logx × sin(bx)
class 11 physics cbse ​

Answer 1

Answer: logx (b) cos(bx)+1/x sin(bx)

Step-by-step explanation:

d(uv)/dx = u dv/dx + v du/dx       (By Product Rule)

d(logx * sin(bx) ) = logx d(sin(bx) )/dx + sin(bx) d(logx)/dx

we know that,

1. d (sinx)/dx = cos x, d (sin(ax))/dx = cos ax * a [where 'a' is constant.]
2. d(logx)/dx = 1/x

So,

d(logx * sin(bx) ) = logx d(sin(bx) )/dx + sin(bx) d(logx)/dx

                          =logx*b* cos (bx) + sin(bx)* 1/x.

Answer 2

Answer:

HOPE IT HELPS YOU