Math, asked by mayureshkathe27, 5 hours ago

differentiate w.r.t.x. sin -1 ( x³)​

Answers

Answered by mukeshkumar23feb
0

Step-by-step explanation:

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Answered by riderboy731
0

Answer

3x²/(1-x)

Step By Step Soln:

As We know that the differentiation of sin-¹x w.r.t. to x is

1/(1-x²)

So According To Chain Rule

d[sin-¹(x³)]/dx = d[sin-¹(x³)]/dx³ × d(x³)/dx

= 1/[√1-(x³)²] × 3x²

= 3x²/(√1-x⁶)

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