Question

Differentiate w.r.t ‘ x ' y=a^2+sin45degree-sec3x

Answer 1

Answer:

-3sec(3x)tan(3x)

Step-by-step explanation:

sin(45°) is constant and

assuming a is constant,

d/dx (-sec3x) = -3sec(3x)tan(3x)  [Chain rule]

if a is not a constant,

d/dx (a² - sec3x) = (2a · da/dx) - 3sec(3x)tan(3x)

[Again Chain rule]

Hoping that I have not made any mistakes, You're welcome.

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GeniusH