Question

Differentiate w. r. t 'x' : ⠀
y = tan [cos(sinx)]​

Answer 1

Answer:

ddx(tan2(x))

This is a composite function

so we must differentiate the square part and then separately differentiate the tan part

ddx(tan2(x))=2tan(x).ddx(tan(x))

ddx(x2)=2.x1

ddx(tan(x))=sec2(x)

Therefore, ddx(tan2(x))=2tan(x).sec2(x)

Step-by-step explanation:

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Answer 2

This is your answer..... .

Step-by-step explanation:

Let y = tan [ cos (since) ]

Differentiating w. r. t. x, we get

dy/ Dx = d/ dx { tan[ cos (sin x )]}

= sec square [ cos (sin x) ]. d/dx [ cos (sin x ) ]

= sec square [ cos (sin x) ]. [ - sin ( sin x) ] . d/dx ( sin x)

= - sec square [ cos (sin x) ]. sin ( sin x) . cos x.