Question

differentiate w.r.t.x. y=√tan√x
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Answer 1

Step-by-step explanation:

$y = \sqrt{ \tan( \sqrt{x} ) }$

differentiate above equation with respect to x

$\frac{dy}{dx} = \frac{1}{2 \sqrt{ \tan( \sqrt{x} ) } } \times \frac{d}{dx} \tan( \sqrt{x} )$

$\: \: \: \: = \frac{1}{2 \sqrt{ \tan( \sqrt{x} ) } } \times \sec^{2} \sqrt{x} \times \frac{d}{dx} \sqrt{x}$

$\: \: \: \: = \frac{ \sec^{2} \sqrt{x} }{2 \sqrt{ \tan( \sqrt{x} ) } } \times \frac{1}{2 \sqrt{x} }$

$\: \: \: \: = \frac{ \sec^{2} (\sqrt{x}) }{4 \sqrt{ \ x.tan( \sqrt{x} ) } }$

your Solution is completed

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