Differentiate w.r.t. x
y= (x+1)^3/x^3/2
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First you should open the brackets.Once you do that, you’ll get a polynomial function . Then do the usual thing..
Here, when you open the brackets, you get : [math]y=[/math]([math]x^2 + x -2) (x + 3) =[/math]
[math](x^3 + 4x^2 + x -6)[/math]
on differentiating this, you get[math] :[/math]
[math]\frac{dy}{dx} = 3x^2 + 8x + 1[/math
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