Question

differentiate with respect to x ​

Answer 1

Answer:

bahut bada differentiation hoga tum agar neet ke ho toh aise questions nahi aayebge

Answer 2

Answer:

$y=\log (\sqrt{\frac{1-x}{1+x}}\right))$

$10^y=\sqrt{\frac{1-x}{1+x}}$

$100^y=\frac{1-x}{1+x}$

$100^y\left(1+x\right)=1-x$

$100^y(x)+x=1-100^y$

$x=\frac{1-100^y}{100^y+1}$