Question

differentiate with respect to x√(ax+b)

Answer 1

Differentiating

y=(ax+b)ny=(ax+b)n

with respect to xx gives us

y′=n(ax+b)n−1⋅(ax+b)′=an(ax+b)n−1.y′=n(ax+b)n−1⋅(ax+b)′=an(ax+b)n−1.



Apply the chain rule to g(x)=ax+bg(x)=ax+band f(x)=xnf(x)

by chain rule... d(ax+b)n/dx=n(ax+b)n−1×d(ax+b)/dx=an(ax+b)n−1