Differentiate with respect to x
e^x . sinx . log x
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its dy/dx =e^x .cosx/x
this is ur answer
this is ur answer
PrernaPurohit:
Thanks but how this I'm not able to understand this question
it is a double diffrentiation means diffrentiate of the already diffrentiated value
tnks
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Thanks for your kind question ,
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Hmmmmmm
Now if you liked my explanation then plsssssss
plsssssss
Hit that explosive button ,named
"The Badge of Glory"
"The Brainliest"
:)
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