Math, asked by Jitu2263, 11 months ago

Differentiate with respect to x e^xlog x

Answers

Answered by Dynamicsreborn
0

Answer:

I think it will be like this:-

=e^xlogx.x1/x + 1/x

=e^xlogx.1+1/x

=e^xlogx.(x+1/x)

I think this would be the answer...

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