Question

Differentiate with respect to x
sin^3(4x+1)

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Answer 1

Answer:

$12cos(4x+1)sin^{2}(4x+ 1 )$

Step-by-step explanation:

  $\frac{d}{dx}(sin^{3}(4x+1))$

= $[3sin^{2}(4x+1)][cos(4x+1)][4]$

= $12cos(4x+1)sin^{2}(4x+ 1 )$