Differentiate with respect to‘ x ’Sin (ax+b)²
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Answer:
Explanation:
Let,
y = sin(ax+b)^2
differentiating with respect to 'x'
dy\dx = cos(ax+b)^2 x 2a(ax+b)
ankita536895:
do step by step
Its all a formulae
I think this answer is wrong
I think this is done by addition and subtraction rule
nah..it's correct
y=sin(ax+b)
y′=dydx−=cos(ax+b).d(ax)x
y′=cos(ax+b).a
y′=acos(ax+b)
y′=dydx−=cos(ax+b).d(ax)x
y′=cos(ax+b).a
y′=acos(ax+b)
like this ... can you understand
no
then? still how
get..the formulas noted once again u would get it
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