Question

differentiate with respect to X tanx / cosx​

Answer 1

Answer:

Let y = tanx/cos x

Use Quotient rule of differentiation,

dy/dx = [ sec^2x cos x - (-sinx) tanx ] / cos^2 x

dy/dx = [ sec x + sin^2x / cos x] / cos^2x

dy/dx = ( 1 + sin^2x ) / cos^3x