Question

differentiate with respect to x

x^5+y^5=5ax²2y²​

Answer 1

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${x}^{5} + {y}^{5} = 5a {x}^{2} + 2 {y}^{2}$

diffrentiate w.r.t. x

$5 {x}^{4} + 5 {y}^{4} . \frac{dy}{dx} = 10ax + 4y. \frac{dy}{dx}$

$5 {x}^{4} - 10ax =( 4y - 5 {y}^{4} ) \frac{dy}{dx}$

$\frac{5 {x}^{4} - 10ax }{4y - 5 {y}^{4} } = \frac{dy}{dx}$