Question

differentiate with respect
to x, y = (log x)(logy to the base a)​

Answer 1

Answer:

(Log(x) to base a)'= 1/[x(ln(a))]. This can be obtained either by implicit differentiation of x = a^y or by first converting log-base-a of x to ln(x) / ln(a). With the denominator just a constant and the derivative of ln(x) being 1 / x, the answer follows immediately.

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