Question

Differentiate with respect to x.
Y = (logex) square
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Answer 1

Answer:

2logx× 1/x

Explanation:

y = (logx)^2

differentiating with respect to x

dy/dx = 2logx /x.

( here, we considered logx as x and then differentiated x^2 which is 2x and then applying chain rule, we have to differentiate the term we considered as x ( here logx ) so it's differentiation is 1/x)

THANK YOU!!

Answer 2

it's your answer of this question