Question

differentiate with respect to x. y=sin(√x/1+x^2)
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Answer 1

Answer:

let ,u = √x / 1 + x²

therefore,

y = sin u

..dy / du = cos u

du / dx =[ (1+x²) (1/2√x) + √x(2x)]/(1+x²)²

dy / dx= dy / du + du /dx

.===>dy/dx= [ (1+x²)(1/2√x)+ √x(2x)]/(1+x²)². X. cos(√x/1+x²)

Step-by-step explanation:

hope it works.

Answer 2

Step-by-step explanation:

maximum height can be attained only when the projectile is launched at 90°

threrfore ,

h= u^2/2g

25×2×9.8= u^2

490=u^2

7√10=u

then for range ,

the maximum range occurs at 45°

R = u^2/g

R = 490/9.8

R = 50 m