Question

differentiate wuth respetvto x :
e^ sin^-1x​

Answer 1

Answer:

Let,

$y = e {}^{sin {}^{ - 1} x}$

$\frac{dy}{dx} = \frac{d(e {}^{sin {}^{ - 1} x} )}{dx}$

$\frac{dy}{dx} = e {}^{sin {}^{ - 1} x} . \frac{1}{ \sqrt{1 - x {}^{2} } }$

Note :

Differentation of $e {}^{x} = e {}^{x}$

Be Brainly!

Answer 2

Answer:

$\frac{d}{dx} {e}^{ {sin}^{ - 1} x} \\ \\ = {e}^{ {sin}^{ - 1}x } \frac{d}{dx} {sin}^{ - 1} x \\ \\ = \frac{ {e}^{ {sin}^{ - 1} x} }{ \sqrt{1 - {x}^{2} } }$