differentiate √(x+1)
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Use n√ax=axn a x n = a x n to rewrite √x−1 as (x−1)12 ( x - 1 ) 1 2 . Differentiate using the chain rule, which states that ddx[f(g(x))] d d x [ f ( g ( x ) ) ] is f'(g(x))g'(x) f ′ ( g ( x ) ) g ′ ( x ) where f(x)=x12 f ( x ) = x 1 2 and g(x)=x−1 g ( x ) = x - 1 . To apply the Chain Rule, set u u as x−1 x - 1 .
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