Question

Differentiate (x-1)/(x-2)​

Answer 1

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Ley y = (x-1)/(x-2)

=> y' = {(x-1)'(x-2) - (x-2)'(x-1)}/(x-2)^2

y' = {x-2 - x+1}/(x-2)^2

y' = -1/(x-2)^2

Thus, differential of (x-1)/(x-2) is -1/(x-2)^2.

Answer 2

Let y = (x-1)/(x-2)

=> y' = {(x-1)'(x-2) - (x-2)'(x-1)}/(x-2)^2

y' = {x-2 - x+1}/(x-2)^2

y' = -1/(x-2)^2

Thus, differential of (x-1)/(x-2) is -1/(x-2)^2.