differentiate (x+1)(x+2) with respect to x
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Step-by-step explanation:
d
d
x
[
f
(
x
)
g
(
x
)
]
is
g
(
x
)
d
d
x
[
f
(
x
)
]
−
f
(
x
)
d
d
x
[
g
(
x
)
]
g
(
x
)
2
where
f
(
x
)
=
x
−
1
and
g
(
x
)
=
x
−
2
.
(
x
−
2
)
d
d
x
[
x
−
1
]
−
(
x
−
1
)
d
d
x
[
x
−
2
]
(
x
−
2
)
2
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