Question

differentiate (x + 1/x)³ with respect to x
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Answer 1

Answer:

$3x^2-3/x^4+ 3 -3/x^2$

Step-by-step explanation:

first we need to open the bracket and expand the expression

$(x+1/x)^{3} = x^3+1/x^3+3x+3/x$

then we will differentiate each term

$\frac{d}{dx} x^3 + \frac{d}{dx}1/x^3 + \frac{d}{dx}3x+ \frac{d}{dx}3/x$

this will result in

$3x^2-3/x^4+ 3 -3/x^2$