Math, asked by vivekyadav12120, 11 months ago

differentiate (√x +1/√x)^5​

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Answered by Anonymous
20

Answer:

y =  (\sqrt{x}  +  \frac{1}{ \sqrt{x} } ) ^{5 }  \\  \\   \frac{dy}{dx}  = 5( \sqrt{x}  +  \frac{1}{ \sqrt{x} } ) ^{4}   \:  \: \frac{d}{dx} ( \sqrt{x}  +  \frac{1}{ \sqrt{x} } ) \\  \\  \frac{dy}{dx}  = 5( \sqrt{x}  +  \frac{1}{ \sqrt{x} } ) (\frac{1}{2 \sqrt{x} }   -  \frac{1}{2}  {x}^{ \frac{ - 3}{2} } ) \\  \\  \frac{dy}{dx}  = (5 \sqrt{x}  +  \frac{5}{ \sqrt{x} } )( \frac{1}{2 \sqrt{x} }  -  \frac{1}{2 {x}^{ \frac{3}{2} } } ) \\  \\  \frac{dy}{dx}  = 5 -  \frac{5 \sqrt{x} }{2 {x}^{ \frac{3}{2} } }  +  \frac{5}{2x}  -  \frac{5}{2 \sqrt{x}  {x}^{ \frac{3}{2} } }

Hope it helps uh☺

Answered by pinks27371
0

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