Question

differentiate (x+1/x)^x with respect to x​

Answer 1

Step-by-step explanation:

y=(x+1/x)^x

y=(x+1/x)^xdy/dx=x(x+1/x)^x-1 ×(x+1-x)/x²

y=(x+1/x)^xdy/dx=x(x+1/x)^x-1 ×(x+1-x)/x²dy/dx={(x+1/x)^x-1}/x