Math, asked by aditichauhan490, 10 months ago

differentiate x^3.tan^5x/tan4x​

Answers

Answered by Anonymous
3

Step-by-step explanation:

let

y = x^3 tan^5x /tan4x

dydx=(3x^2tan^5x+5tan^4xsec^2x*x^3tan4x - 4tan4x*x^3 tan^5x)/tan^24x

Answered by wwwyogeshrr
0

Answer:

Step-by-step explanation:

y = x^3 tan^5x /tan4x

dydx=(3x^2tan^5x+5tan^4xsec^2x*x^3tan4x - 4tan4x*x^3 tan^5x)/tan^24x

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