Question

differentiate x^3 +y^3
= 3axy
​

Answer 1

Answer:

x^3+y^3=3axy

differentiating with respect to X

3x^2+3y^2dy/dx=3ay+3axdy/dx

dy/dx=3(ay - x^2)/(3y^2- 3ax)

Answer 2

concept

d(x^n)/dx = nx^n-1

step by step explanation

$x {}^{3} + y {}^{3} = 3axy$

differentiate with respect respect to X

by using chain rule .

$3x {}^{2} + 3y {}^{2} \times \frac{dy}{dx} = 3ay + 3ax \frac{dy}{dx}$

$\frac{dy}{dx} (3ax - 3y {}^{2} ) = 3x {}^{2} - 3ay$

$\frac{dy}{dx} = \frac{3x {}^{2} - 3ay }{3ax - 3y {}^{2} }$

$\frac{dy}{dx} = \frac{ {x}^{2} - ay }{ax - y {}^{2} }$

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