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differentiate x cube + sin x with respect to X

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Answered by zunnairailyas177
2

y = x^3 + sinx.........(1)

Differentiate equation 1 with respect to "x"

dy/dx = d/dx (x^3 + sinx)

dy/dx = d/dx(x^3) + d/dx (sinx)

Derivative of sinx is cos x,

hence

dy/dx = 3x^{2} + cos x


DETAILED EXPLANATION OF THE METHOD

Differentiation is that the action of computing a by-product. The by-product of a perform y = f(x) of a variable x may be a live of the speed at that the worth y of the perform modifications with relation to the change of the variable x. it's referred to as the by-product of f with relation to x.

Differentiation and integration will facilitate North American country solve many sorts of real-world issues. we have a tendency to use the by-product to see the most and minimum values of explicit functions (e.g. cost, strength, quantity of fabric employed in a building, profit, loss, etc.).

Answered by best17
1

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