Math, asked by tankh2007, 3 months ago

differentiate x qube+3xsquare+x​

Answers

Answered by tennetiraj86
0

Step-by-step explanation:

Given that

+3x²+x

on differentiating with respect to x

=d/dx (+3x²+x)

=>d/dx ()+d/dx (3x²)+d/dx (x)

=>3x²+6x+1

Answer=3x²+6x+1

Answered by mukilasebi46
0

Answer:

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Step-by-step explanation:

d/dx(x^n)= nx^n-1.

d/dx(x^3)= 3x^2.

d/dx(3x^2)=6x.

d/dx(x)=1.

Answer is 3x^2+6x+1.

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