differentiate x qube+3xsquare+x
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Step-by-step explanation:
Given that
x³+3x²+x
on differentiating with respect to x
=d/dx (x³+3x²+x)
=>d/dx (x³)+d/dx (3x²)+d/dx (x)
=>3x²+6x+1
Answer=3x²+6x+1
Answered by
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Answer:
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Step-by-step explanation:
d/dx(x^n)= nx^n-1.
d/dx(x^3)= 3x^2.
d/dx(3x^2)=6x.
d/dx(x)=1.
Answer is 3x^2+6x+1.
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