Question

Differentiate√x- secx+ logx write to x​

Answer 1

Step-by-step explanation:

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Answer 2

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y=log(secx+tanx)

differentiating w.r to x

dxdy=dxd(log(secx+tanx))

       =secx+tanx1.(secxtanx+sec2x)

       =(secx+tanx)secx(tanx+secx)

dxdy=secx

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