differentiate x^sinx
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Answered by
1
Answer:
sorry i dont know bhaiya maaf kardo
Answered by
1
Answer:
Step-by-step explanation:
assume the question as y
y=x^sin x
take log on both sides
log y=sin x *log x
differentiating with respect to x
1/y dy/dx=(sin x/x)+x cos x
dy/dx=x^sin x{ (sin x/x)+x cos x}
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