Question

differentiate (x²-2+x)^2
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Answer 1

Answer:

dy/dx=2(2x+1)(x²-2+x)

Step-by-step explanation:

let y= (x²-2+x)^2

and z=x²-2+x

then y=z²

dy/dz=2z=2(x²-2+x)----------------(1)

dz/dx=d/dx(x²-2+x)=2x+1--------(2)

Hence

dy/dx=dy/dz*dz/dx

putting values from (1) and (2) we get

dy/dx=2(x²-2+x)*(2x+1)

hence dy/dx=2(2x+1)(x²-2+x)