Differentiate : x² + 4x²-3x+5.
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is me difference nahi nikala jata
just solve kiya jata he..
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=d(x^3+4c^2-3x+5)/dx
=d(x^3)/dx+4d(x^2)/dx-3d(x)/dx+d(5)/dx
=3x^2+4(2x) -3+0
=3x^2+8x-3
=d(x^3)/dx+4d(x^2)/dx-3d(x)/dx+d(5)/dx
=3x^2+4(2x) -3+0
=3x^2+8x-3
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