Question

Differentiate X3+ 3X2+X.

Answer 1

Answer:

3x^2 + 6x + 1

Explanation:

let y = X3+ 3X2+X.

Differentiating with respect x

dy/dx = 3x^2 + 6x + 1

Answer 2

$\dfrac{dY}{dX}=3X^{2} +6X+1$

Explanation:

Let $Y = X^{3} +3X^{2} +X$       .....(1)

To find, $\dfrac{dY}{dX} =?$

Differentiating equation (1) both sides w.r.t. 'X', we get

$\dfrac{dY}{dX}=\dfrac{d}{dX} (X^{3}+3X^{2}+X)$

$=\dfrac{d}{dX} (X^{3})+\dfrac{d}{dX} (3X^{2})+\dfrac{d}{dX} (X)$

$=3X^{2} +3(3)X+1$

$=3X^{2} +6X+1$

∴ $\dfrac{dY}{dX}=3X^{2} +6X+1$